// 易错点5：必须将当前元素入栈（作为左侧元素的候选更大值，漏写则栈始终为空）
for (int i = 0; i < n1; i++) {
。关于这个话题，服务器推荐提供了深入分析
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“技防”还是不如“人防”
In a live demo, Gore walked through how a new developer with no prior credentials spins up an identity, joins a Linux Foundation community, and then establishes a relationship with another participant using pairwise DIDs. Once that relationship exists, the two sides can exchange richer, verifiable relationship credentials (VRCs) that record facts such as when the relationship started, the level of trust it reflects, and how long the credential should remain valid.